document.write( "Question 854618: From each corner of a square piece of sheet metal 18 centimeters on a side, remove a small square of the side x centimeters and turn up the edges to form an open box. What should the dimensions of the box be to maximize the volume?\r
\n" ); document.write( "\n" ); document.write( "I tried drawing a picture for this problem to see if it would help me solve it but I'm still lost! Thank you for your help.\r
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Algebra.Com's Answer #514797 by josgarithmetic(39629)\"\" \"About 
You can put this solution on YOUR website!
Try to first draw the two-dimensional net. Deal with the VOLUME calculation later. You will start with a square.\r
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\n" ); document.write( "\n" ); document.write( "The original square is 18 cm by 18 cm. Draw the picture and revise accordingly:
\n" ); document.write( "Remove a square at each corner of dimensions x by x. This means the dimensions of what will become the base of the box are (18-2x) by (18-2x). \r
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\n" ); document.write( "\n" ); document.write( "With the square corners removed, folding up the flaps forms the box of height x. Be SURE you understand that.\r
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\n" ); document.write( "\n" ); document.write( "WHAT IS THE VOLUME?\r
\n" ); document.write( "\n" ); document.write( "It is a variable according to the formula \"highlight%28v=x%2818-2x%29%2818-2x%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "The x intercepts are very easy to locate. You can either use a graphing calculator to find the maximum volume; or you can, if you understand these, find the derivative of v versus x and look for the maximum v that way.\r
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\n" ); document.write( "\n" ); document.write( "The maximum volume occurs at x=3.
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