document.write( "Question 854617: There were some beans in Jars A, B and C. Jar A contained 20% of the total number of beans. The ratio of the number of beans in Jar B to the total number of beans in Jars A and C was 2:1. There were 152 more beans in Jar B than C. How many beans were there in Jar A? How many beans were there in the three jars altogether? \n" ); document.write( "
Algebra.Com's Answer #514780 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! There were some beans in Jars A, B and C. Jar A contained 20% of the total number of beans. The ratio of the number of beans in Jar B to the total number of beans in Jars A and C was 2:1. There were 152 more beans in Jar B than C. How many beans were there in Jar A? How many beans were there in the three jars altogether? \n" ); document.write( "------ \n" ); document.write( "Equations: \n" ); document.write( "Let x be the total number of beans. \n" ); document.write( "A = 0.2x \n" ); document.write( "C = B-152 \n" ); document.write( "B = 2(A+C) = 2A+2C = 0.4x + 2C = 0.4x+2(B-152) = 0.4x+2B-304 \n" ); document.write( "So B = 0.4x + 2B - 304 \n" ); document.write( "Then 0.4x + B - 304 = 0 \n" ); document.write( "B = 304-0.4x \n" ); document.write( "----------------------- \n" ); document.write( "A + B + C = x \n" ); document.write( "0.2x + (304-0.4x) + ((304-0.4x)-152) = x \n" ); document.write( "-0.6x +304+152 = 0 \n" ); document.write( "-0.6x + 456 = 0 \n" ); document.write( "x = 760 beans \n" ); document.write( "---- \n" ); document.write( "Jar A has 0.2x = 152 beans \n" ); document.write( "-------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |