document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=854606>Question 854606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi tutors<BR>\n" );
document.write( "a bottle of hydrogen peroxide (solute) dissolved in water (solvent) has a concentration of 48%. If the amount of dissolved hydrogen peroxide is .32 liter, how much solution is in the bottle? rounded to the nearest hundredth \r<BR>\n" );
document.write( "\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514772 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That would be expected 48% weight per weight. This site, http://www.h2o2.com/technical-library/physical-chemical-properties/physical-properties/default.aspx?pid=11&name=Density-of-H2O2-Solutions, indicates the density is about 1.19 g/ml.  That also indicates 1.45 g/ml for 100% hydrogen peroxide.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "320 ml. of hydrogen peroxide is 0.32 liter of it.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=320%2Aml%2A1.45%28gram%2Fml%29=highlight%28464%2Agrams%29 ALIGN=MIDDLE  ALT=\"320%2Aml%2A1.45%28gram%2Fml%29=highlight%28464%2Agrams%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > of hydrogen peroxide.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=48%2F100=464%2FS ALIGN=MIDDLE  ALT=\"48%2F100=464%2FS\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where S is the mass in grams, of HYDROGEN PEROXIDE SOLUTION, 48%.<BR>\n" );
document.write( "-<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%2F464=100%2F48 ALIGN=MIDDLE  ALT=\"S%2F464=100%2F48\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S=464%28100%2F48%29 ALIGN=MIDDLE  ALT=\"S=464%28100%2F48%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28S=966%262%2F3%2Agrams%29 ALIGN=MIDDLE  ALT=\"highlight%28S=966%262%2F3%2Agrams%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > of 48% solution<BR>\n" );
document.write( "-<BR>\n" );
document.write( "To put this into volume, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=966%262%2F3%2Agrams%28%281%2Aml%29%2F%281.19%2Agrams%29%29=highlight%28812%2Aml%29 ALIGN=MIDDLE  ALT=\"966%262%2F3%2Agrams%28%281%2Aml%29%2F%281.19%2Agrams%29%29=highlight%28812%2Aml%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which should be 810 ml, to TWO SIGNIFICANT FIGURES. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );