document.write( "Question 854346: If I am traveling at 90 mph and a car is a quarter mile behind me, how fast must that car (mph) go to catch me within a quarter mile? \n" ); document.write( "
Algebra.Com's Answer #514689 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
I will travel .25 miles at 90 mph
\n" ); document.write( "Other car will travel .50 miles at 90+y mph\r
\n" ); document.write( "\n" ); document.write( "90x=.25,
\n" ); document.write( "(90+y)*x=.50
\n" ); document.write( "x = 1/360, y = 90
\n" ); document.write( "The second car must go 180 mph for 60*1/360=1/6 minute= 10 seconds\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );