document.write( "Question 854124: The dimensions of a rectangle are such that its length is 11in more than its width.
\n" ); document.write( "If the length were doubled and if the width were decreased by 5 in, the area would be increased by 10in^2.
\n" ); document.write( "What are the length and width of the rectangle?
\n" ); document.write( "

Algebra.Com's Answer #514598 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "The dimensions of a rectangle are such that its length is 11in more than its width.
\n" ); document.write( "If the length were doubled and if the width were decreased by 5 in, the area would be increased by 10in^2.
\n" ); document.write( "What are the length and width of the rectangle?
\n" ); document.write( "

\n" ); document.write( "Original width: \"highlight_green%2810.4658561%29\" inches
\n" ); document.write( "Original length: \"highlight_green%2821.4658561%29\" inches
\n" ); document.write( "You can do the check!! \r
\n" ); document.write( "\n" ); document.write( "If you need a complete and detailed solution, let me know!!\r
\n" ); document.write( "\n" ); document.write( "Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. \n" ); document.write( "
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