document.write( "Question 854305: Sketch a triangle that has acute angle θ, and find the other five trigonometric ratios of θ.\r
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Algebra.Com's Answer #514569 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "You were to sketch a triangle, not a circle.\r\n" );
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document.write( "cot(θ)=1\r\n" );
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document.write( "The cotangent is the adjacent over the opposite.\r\n" );
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document.write( "Write the 1 as \"1%2F1\"\r\n" );
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document.write( "\"cot%28theta%29=1%2F1\"\r\n" );
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document.write( "Then when we draw the right triangle, we will make the adjacent side\r\n" );
document.write( "to \"theta\" equal to the numerator of \"1%2F1\", which is 1 and the opposite\r\n" );
document.write( "side of \"theta\" equal to the denominator of \"1%2F1\" which is 1 as well, so the\r\n" );
document.write( "right triangle is:\r\n" );
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document.write( "Now we calculate the hypotenuse by the Pythagorean theorem:\r\n" );
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document.write( "\"hypotenuse%5E2=adjacent%5E2%2Bopposite%5E2\"\r\n" );
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document.write( "\"hypotenuse%5E2=1%5E2%2B1%5E2\"\r\n" );
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document.write( "\"hypotenuse%5E2=1%2B1\"\r\n" );
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document.write( "\"hypotenuse%5E2=2\"\r\n" );
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document.write( "\"sqrt%28hypotenuse%5E2%29=sqrt%282%29\"\r\n" );
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document.write( "\"hypotenuse+=+sqrt%282%29\"\r\n" );
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document.write( "Now the adjacent side = 1, the opposite side = 1, \r\n" );
document.write( "and the hypotenuse = \"sqrt%282%29\"\r\n" );
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document.write( "\"sin%28theta%29=opposite%2Fhypotenuse=1%2Fsqrt%282%29=sqrt%282%29%2F2\"\r\n" );
document.write( "\"cos%28theta%29=adjacent%2Fhypotenuse=1%2Fsqrt%282%29=sqrt%282%29%2F2\"\r\n" );
document.write( "\"tan%28theta%29=opposite%2Fadjacent=1%2F1=1\"\r\n" );
document.write( "\"sec%28theta%29=hypotenuse%2Fadjacent=sqrt%282%29%2F1=sqrt%282%29\"\r\n" );
document.write( "\"csc%28theta%29=hypotenuse%2Fopposite=sqrt%282%29%2F1=sqrt%282%29%2F2\"\r\n" );
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document.write( "And you were already given:\r\n" );
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document.write( "\"cot%28theta%29=adjacent%2Fopposite=1%2F1=1\"\r\n" );
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document.write( "Edwin
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