document.write( "Question 854107: eric is two years older than his wife canoy. in 15 years, the sum of their ages will be 1 more than thrice eric is age now. how old are they now?
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Algebra.Com's Answer #514539 by ankor@dixie-net.com(22740)\"\" \"About 
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let e = Eric's age
\n" ); document.write( "let c = Canoy's age
\n" ); document.write( "Write an equation for each statement, simplify as much as possible.
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\n" ); document.write( "eric is two years older than his wife canoy.
\n" ); document.write( "e = c + 2
\n" ); document.write( " in 15 years, the sum of their ages will be 1 more than thrice eric is age now.
\n" ); document.write( "(e+15) + (c+15) = 3e + 1
\n" ); document.write( "e + c + 30 = 3e + 1
\n" ); document.write( "c + 30 - 1 = 3e - e
\n" ); document.write( "c + 29 = 2e
\n" ); document.write( "Replace e with (c+2)
\n" ); document.write( "c + 29 = 2(c+2)
\n" ); document.write( "c + 29 = 2c + 4
\n" ); document.write( "29 - 4 = 2c - c
\n" ); document.write( "25 = c
\n" ); document.write( "Canoy is 25 yrs old. You can find Eric's age, check your solutions in the 2nd statement\r
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