document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=853832>Question 853832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Identify the center of the conic section whose equation is x 2 + y 2 + 6 x - 4 y - 12 = 0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514517 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Identify the center of the conic section whose equation is <BR>\n" );
document.write( "x 2 + y 2 + 6 x - 4 y - 12 = 0.<BR>\n" );
document.write( "x^2+6x+y^2-4y-12=0<BR>\n" );
document.write( "complete the square:<BR>\n" );
document.write( "(x^2+6x+9)+(y^2-4y+4)=12+9+4<BR>\n" );
document.write( "(x+3)^2+(y-2)^2=25<BR>\n" );
document.write( "This is an equation of a circle with center at (-3,2) and radius of 5 </SPAN>\n" );
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