document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=854119>Question 854119</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm thinking of a number whose differences is 50. Twice the larger number equals three times the smaller number. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514509 by </B><A HREF=/tutors/aboutme.mpl?userid=aditya2117><B>aditya2117(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=aditya2117><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=aditya2117><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514509\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the nos. be x and y.<BR>\n" );
document.write( "Accordingly,<BR>\n" );
document.write( "            x-y =50<BR>\n" );
document.write( "            2x = 3y<BR>\n" );
document.write( "So,   x= 50 +y<BR>\n" );
document.write( "   => 2x = 100+2y<BR>\n" );
document.write( "   => 3y - 2y = 100 [Since 2x=3y]<BR>\n" );
document.write( "   => y=100<BR>\n" );
document.write( "therefore, x= 50+y = 50+100=150<BR>\n" );
document.write( "Ans: The nos. are 100 and 150. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );