document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=854124>Question 854124</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The dimensions of a rectangle are such that its length is 11in more than its width. <BR>\n" );
document.write( "If the length were doubled and if the width were decreased by 5 in, the area would be increased by 10in^2.<BR>\n" );
document.write( "What are the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514495 by </B><A HREF=/tutors/aboutme.mpl?userid=aditya2117><B>aditya2117(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=aditya2117><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=aditya2117><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be x inches.<BR>\n" );
document.write( "Length = (x+11) inches<BR>\n" );
document.write( "Area= x(x+11) sq.inches<BR>\n" );
document.write( "Now As per question,<BR>\n" );
document.write( "2(x+11)(x-5)= x(x+11) + 10^2<BR>\n" );
document.write( "=> 2(x^2+6x-55)=x^2+11x+100<BR>\n" );
document.write( "=> 2x^2+12x-110=x^2+11x+100<BR>\n" );
document.write( "=> 2x^2-x^2+12x-11x-110-100=0<BR>\n" );
document.write( "=> x^2 + x - 210 = 0<BR>\n" );
document.write( "=> x^2 + 15x - 14x - 210 = 0<BR>\n" );
document.write( "=> x(x+15)-14(x+15)=0<BR>\n" );
document.write( "=> (x+15)(x-14)=0<BR>\n" );
document.write( "Therefore, <BR>\n" );
document.write( "          x = -15 or 14<BR>\n" );
document.write( "But measurement # negetive<BR>\n" );
document.write( "So, x=14<BR>\n" );
document.write( "    x+11 = 25<BR>\n" );
document.write( "Ans: Length is 25 inches and width is 14 inches. </SPAN>\n" );
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