document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=854175>Question 854175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> End points of the radius are (-6,-2) and (4,2) , center is in the 3rd quadrant . </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514473 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Clever way to say that the center is (-6,-2).  The radius is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=sqrt%28%28-6-4%29%5E2%2B%28-2-2%29%5E2%29 ALIGN=MIDDLE  ALT=\"r=sqrt%28%28-6-4%29%5E2%2B%28-2-2%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=sqrt%28100%2B16%29 ALIGN=MIDDLE  ALT=\"r=sqrt%28100%2B16%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=sqrt%28116%29 ALIGN=MIDDLE  ALT=\"r=sqrt%28116%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >,    116=2*58=2*2*29\r<BR>\n" );
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document.write( "Equation of the circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28%28x%2B6%29%5E2%2B%28y%2B2%29%5E2=116%29 ALIGN=MIDDLE  ALT=\"highlight%28%28x%2B6%29%5E2%2B%28y%2B2%29%5E2=116%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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