document.write( "Question 854097: suppose that women's body temperatures are normally distributed with a mean of 98.4 F and a standard devidation of 0.70 F. what is the 95th percentile of womens body temperatures. \n" ); document.write( "
Algebra.Com's Answer #514434 by stanbon(75887)\"\" \"About 
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suppose that women's body temperatures are normally distributed with a mean of 98.4 F and a standard devidation of 0.70 F. what is the 95th percentile of womens body temperatures
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\n" ); document.write( "Find the z-value with a left-tail of 0.95:: invNorm(0.95) = 1.645
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\n" ); document.write( "Find the corresponding body temperature
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\n" ); document.write( "x = z*s + u
\n" ); document.write( "x = 1.645*0.7 + 98.4 = 99.55 degrees
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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