document.write( "Question 854097: suppose that women's body temperatures are normally distributed with a mean of 98.4 F and a standard devidation of 0.70 F. what is the 95th percentile of womens body temperatures. \n" ); document.write( "
Algebra.Com's Answer #514434 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! suppose that women's body temperatures are normally distributed with a mean of 98.4 F and a standard devidation of 0.70 F. what is the 95th percentile of womens body temperatures \n" ); document.write( "---------------- \n" ); document.write( "Find the z-value with a left-tail of 0.95:: invNorm(0.95) = 1.645 \n" ); document.write( "----- \n" ); document.write( "Find the corresponding body temperature \n" ); document.write( "----- \n" ); document.write( "x = z*s + u \n" ); document.write( "x = 1.645*0.7 + 98.4 = 99.55 degrees \n" ); document.write( "---------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |