document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=853991>Question 853991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi I am a student in algebra 2 and we are solving linear equalities for the values of x, y, z and I am extremely confused on how to solve this problem x+z=3 and x+2y-z=1 and 2x-y+z=3 please help me I am super confused </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514381 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514381\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What method do you want to use?  Try substitution if this is allowed for your class right now.\r<BR>\n" );
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document.write( "z=3-x from the first equation.  The next two equations using this substitution are:<BR>\n" );
document.write( "x+2y-(3-x)=1 and 2x-y+(3-x)=3;<BR>\n" );
document.write( "2x+2y-3=1 and x-y+3=3;<BR>\n" );
document.write( "2x+2y=4 and x-y=0;<BR>\n" );
document.write( "x+y=2 and x-y=0;<BR>\n" );
document.write( "Using simple elimination, adding left members and adding right members gives:<BR>\n" );
document.write( "2x=2 which means x=1.  This also means, using x-y=0 that y=1.\r<BR>\n" );
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document.write( "Use the first equation now to find the value for z. </SPAN>\n" );
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