document.write( "Question 853920: -could you please help me in this problem\r
\n" ); document.write( "\n" ); document.write( "solve for x:
\n" ); document.write( " ln(x-1)=ln(x-2)-ln x
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Algebra.Com's Answer #514343 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Two rules to know.
\n" ); document.write( "\"ln%28ab%29=ln%28a%29%2Bln%28b%29\"; also, \"ln%28a%2Fb%29=ln%28a%29-ln%28b%29\".
\n" ); document.write( "Other rule is that if \"log%28k%2Ca%29=log%28k%2Cb%29\", then \"a=b\".\r
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\n" ); document.write( "\n" ); document.write( "Try using those rules for your given exercise.
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