document.write( "Question 853896: -1/2 less than or equal to 3x-1/10 <1/2
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Algebra.Com's Answer #514336 by aditya2117(32) You can put this solution on YOUR website! => 3x-1/10 <= 1/2 \n" ); document.write( "=> 3x-1 <= 10/2 = 5 \n" ); document.write( "=> 3x <= 6 \n" ); document.write( "=> x<=2 \n" ); document.write( "Ans. x less than or equal to 2 \n" ); document.write( " |