document.write( "Question 853824: gary is twice as old as pat. twenty years ago, gary was six times as old as pat. what are their present age? \n" ); document.write( "

Algebra.Com's Answer #514319 by chndnbl(31) $\"\"$ $\"About$

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Let pat present age be x.
\n" ); document.write( "Then gray present age is 2x.
\n" ); document.write( "20 years ago,
\n" ); document.write( "pat age=x-20
\n" ); document.write( "gray age=6(2x-20)
\n" ); document.write( "then we get,
\n" ); document.write( "2x / x = 6(2x-20) / x-20
\n" ); document.write( "2(x-20) = 6(2x-20)
\n" ); document.write( "2x - 40=12x - 120
\n" ); document.write( "12x - 2x = 120 - 40
\n" ); document.write( "10x = 80
\n" ); document.write( "x = 8 years and
\n" ); document.write( "gray present age =2x=16 years \n" ); document.write( "

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