document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=853841>Question 853841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two positive integers is 9. Twice the first integer plus thrice the second integer is 22. Determine the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514298 by </B><A HREF=/tutors/aboutme.mpl?userid=chndnbl><B>chndnbl(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chndnbl><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chndnbl><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the positive integer be x and y.<BR>\n" );
document.write( "From the first condition:<BR>\n" );
document.write( "x +  y = 9<BR>\n" );
document.write( "from the second condition:<BR>\n" );
document.write( "2x +  3y =22<BR>\n" );
document.write( "multiplying 3 to equation (1).<BR>\n" );
document.write( "3x +  3y =27<BR>\n" );
document.write( " Then solving by elimination method .<BR>\n" );
document.write( " x =5 <BR>\n" );
document.write( "then substituting the value of x in (1)<BR>\n" );
document.write( "y=9-5=4<BR>\n" );
document.write( "y=4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );