document.write( "Question 853814: Hi! Please help me with this.\r
\n" ); document.write( "\n" ); document.write( "The scores of students in the NAT is normally distributed with a mean of 60 and a standard deviation of 8. If 50 students took the test, how many got scores above 36?\r
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Algebra.Com's Answer #514285 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "mean of 60 and a standard deviation of 8.  Sample SD = 8/√50 = 1.1314
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document.write( " z = (60-36)/1.1314 = -3.3941  NORMSDIST(-3.3941) = .0003
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document.write( "Percentage above 36 = 1 - (percentage below) 
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document.write( "                      1 - .0003 = .9997  0r  99.97% have scores above 36
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document.write( "how many got scores above 36?  Probability of ALL of them is VERY good
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document.write( " .9997 * 50 = 49.985   
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