document.write( "Question 853758: In a normal distribution with a mean of 330 and a standard deviation of 60 what are the 45th and 80th percentile values? \n" ); document.write( "

Algebra.Com's Answer #514275 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "mean of 330 and a standard deviation of 60,
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document.write( "45%, z = NORMSINV(.45) = -.1257 ,  z = NORMSINV(.80) = .8416
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document.write( " -.1257 = (X -330)/60
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document.write( "X = 60(-.1257) + 330 = 323, rounded Up
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document.write( "X = 60(.8416) + 330 = 381, rounded Up
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