document.write( "Question 853754: a man drove at a constant speed from his city 180 miles away. On the return trip, he increased his constant speed by 5 mph and made the return trip in 24 minutes less time than had been required to drive to the city. What was his sped from home to the city? \n" ); document.write( "
Algebra.Com's Answer #514223 by mananth(16946)\"\" \"About 
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Time taken in forward journey = 180/x
\n" ); document.write( "x is the speed\r
\n" ); document.write( "\n" ); document.write( "return journey speed increased by 5 mph. (x+5)\r
\n" ); document.write( "\n" ); document.write( "Time forward - time return = 24/60 = 2/5 hours\r
\n" ); document.write( "\n" ); document.write( "\"180%2Fx+-+180%2F%28x%2B5%29+=+2%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "Take LCM of denominator
\n" ); document.write( "5x(x+5)\r
\n" ); document.write( "\n" ); document.write( "180*5*(x+5) -180*5*x=2*x*(x+5)\r
\n" ); document.write( "\n" ); document.write( "900x+4500-900x=2x^2+10x\r
\n" ); document.write( "\n" ); document.write( "2x^2+10x-4500=0
\n" ); document.write( "/2
\n" ); document.write( "x^2+5x-2250=0\r
\n" ); document.write( "\n" ); document.write( "x^2+50x-45x-2250=0\r
\n" ); document.write( "\n" ); document.write( "x(x+50)-45(x+50)=0\r
\n" ); document.write( "\n" ); document.write( "(x+50)(x-45)=0
\n" ); document.write( "x= -50 OR 45\r
\n" ); document.write( "\n" ); document.write( "Speed from home was 45 mph\r
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