document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=853686>Question 853686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (3Square root of 2 -9)(3 square root of 2+9) HOW DO I SOLVE THAT  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514218 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  ((3Sqrt2) -9)((3Sqrt  2)+9)=<BR>\n" );
document.write( "use FOIL<BR>\n" );
document.write( "3Sqrt2*3Sqrt2=9*2=18<BR>\n" );
document.write( "-9*3Sqrt+<BR>\n" );
document.write( "9*3Sqrt2<BR>\n" );
document.write( "-81<BR>\n" );
document.write( "=<BR>\n" );
document.write( "-63 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );