document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=853723>Question 853723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Car A leaves at 8 am at 40 mph. Car b leaves 2 hours later at 60 mph.  How long does it take car b to up,to,car a? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514204 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The distance travelled by the cars is the same when the second catches up with the first.\r<BR>\n" );
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document.write( "Let the first car (A) take x hours for the distance\r<BR>\n" );
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document.write( "distance traveled by car A = 40x\r<BR>\n" );
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document.write( "Car B takes 2 hours less , (x-2) hours\r<BR>\n" );
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document.write( "distance = 60(x-2)\r<BR>\n" );
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document.write( "60(x-2)=40x\r<BR>\n" );
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document.write( "60x-120=40x\r<BR>\n" );
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document.write( "20x=120<BR>\n" );
document.write( "x=6 hours\r<BR>\n" );
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document.write( "Time taken by car B = (x-2) = 4 hours to catch up </SPAN>\n" );
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