document.write( "Question 853445: dave wants to purchase 25 pounds of party mix for a total of $37. to obtain the mixture, he will mix nuts that cost $3 per pound with pretzels that cost $1 per pound. how many pounds of each type and mix should he use?
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Algebra.Com's Answer #514099 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
This is also a mixture problem.\r
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\n" ); document.write( "\n" ); document.write( "Account for cost and account for pounds of foods.\r
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\n" ); document.write( "\n" ); document.write( "COST: n for nuts, p for pretzels, \"1%2Ap%2B3%2An=37\" or simply \"p%2B3n=37\".\r
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\n" ); document.write( "\n" ); document.write( "POUNDS: \"p%2Bn=25\".\r
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\n" ); document.write( "\n" ); document.write( "Obviously more easily viewed as a linear system problem. Two equations in the two unknowns p and n. Elimination Method here can be done mentally, at least for finding n.
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\n" ); document.write( "\"2n=12\" meaning \"highlight%28n=6%29\", therefore \"highlight%28p=19%29\".\r
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\n" ); document.write( "More formally, coefficients on p in both equations are 1.
\n" ); document.write( "\"%28p%2B3n%29-%28p%2Bn%29=37-25\"
\n" ); document.write( "\"p%2B3n-p-n=12\"
\n" ); document.write( "\"3n-n=12\"
\n" ); document.write( "\"2n=12\" therefore \"n=12%2F2=6\"
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