document.write( "Question 853441: I am working on Algebra, Systems of Equations and Inequalities. I am very confused. The question is\r
\n" ); document.write( "\n" ); document.write( "SUBSTITUTION
\n" ); document.write( "Use substitution to solve each system of equations.\r
\n" ); document.write( "\n" ); document.write( "\"+x=3y+\"
\n" ); document.write( "\"+2x%2B3y=15+\"
\n" ); document.write( " x=
\n" ); document.write( " y= \r
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\n" ); document.write( "\n" ); document.write( "\"+x-2y=4+\"
\n" ); document.write( "\"+3x=6y%2B12+\"
\n" ); document.write( " x=
\n" ); document.write( " y= \r
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\n" ); document.write( "\n" ); document.write( "\"+x=5y-2+\"
\n" ); document.write( "\"+2x%2B2y=4+\"
\n" ); document.write( " x=
\n" ); document.write( " y=
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Algebra.Com's Answer #514095 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
Let's look at the first one.
\n" ); document.write( "x = 3y
\n" ); document.write( "2x + 3y = 15
\n" ); document.write( ".
\n" ); document.write( "To solve this using substitution, take the known value of X from the first equation and put it into the second equation.
\n" ); document.write( ".
\n" ); document.write( "2x + 3y = 15
\n" ); document.write( "2(3y) + 3y = 15 (substituted the 3y in place of the X)
\n" ); document.write( "Multiply
\n" ); document.write( "6y + 3y = 15
\n" ); document.write( "Add
\n" ); document.write( "9y = 15
\n" ); document.write( "Divide each side by 9
\n" ); document.write( "Y = \"15%2F9\"
\n" ); document.write( "If y = 1\"2%2F3\", then x = 3 * 1\"2%2F3\", or 5 [x=3y from the first equation]
\n" ); document.write( ".
\n" ); document.write( "Use the same method to solve the others. If you need further help, please post questions one at a time.
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