document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=853410>Question 853410</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man spent 1/6 of his life in childhood, 1/12 in youth and 1/7 more as a bachelor. Five years after his marriage there was a son who died four years before his father at 1/2 his father's final age </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514085 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514085\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1-(1/6+1/12+1/7) =11/28<BR>\n" );
document.write( "17/28 as a bachelor<BR>\n" );
document.write( " 11/28 of his life was after he married.<BR>\n" );
document.write( "see <BR>\n" );
document.write( "http://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.194190.html\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );