document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846479>Question 846479</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The shortest side of a triangle with perimeter 35cm is 5cm.calculate the length of the other two sides if they are in a geometric progression </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514063 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5+5x+5x^2=35<BR>\n" );
document.write( "5x+5x^2=30<BR>\n" );
document.write( "x+x^2=6<BR>\n" );
document.write( "x^2+x-6=0<BR>\n" );
document.write( "(x-2)*(x+3)=0<BR>\n" );
document.write( "x=-3 reject for perimeter<BR>\n" );
document.write( "x=2\r<BR>\n" );
document.write( "\n" );
document.write( "5+10+20=35\r<BR>\n" );
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document.write( " </SPAN>\n" );
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