document.write( "Question 853335: When flying directly into a 25mph wind it takes an aircraft 1 hour longer to travel 300 miles than when there is no wind. Find the time required for the aircraft to fly this distance in no wind. \n" ); document.write( "
Algebra.Com's Answer #514047 by mananth(16946)\"\" \"About 
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let the speed with no wind be x mph\r
\n" ); document.write( "\n" ); document.write( "speed against wind = (x-25)\r
\n" ); document.write( "\n" ); document.write( "distance = 300 miles\r
\n" ); document.write( "\n" ); document.write( "according to the condition\r
\n" ); document.write( "\n" ); document.write( "Time against wind - time with no wind = 1\r
\n" ); document.write( "\n" ); document.write( "300/(x-25) - 300/x = 1\r
\n" ); document.write( "\n" ); document.write( "Take the LCM\r
\n" ); document.write( "\n" ); document.write( "300x-300(x-25) = x(x-25)\r
\n" ); document.write( "\n" ); document.write( "300x-300x+7500= x^2- 25x\r
\n" ); document.write( "\n" ); document.write( "x^2-25x-7500=0\r
\n" ); document.write( "\n" ); document.write( "x^2-100x+75x-7500=0\r
\n" ); document.write( "\n" ); document.write( "x(x-100)+75(x-100)=0\r
\n" ); document.write( "\n" ); document.write( "(x-100)(x+75) =0\r
\n" ); document.write( "\n" ); document.write( "taking the positive value x = 100\r
\n" ); document.write( "\n" ); document.write( "speed with no wind = 100 mph\r
\n" ); document.write( "\n" ); document.write( "d=300
\n" ); document.write( "speed = 100
\n" ); document.write( "t= 3 hours\r
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