document.write( "Question 853340: A teacher randomly hands back test papers to 4 students. In how many ways can all 4 students receive someone else's paper?\r
\n" ); document.write( "\n" ); document.write( "I think the solution uses the following reasoning:
\n" ); document.write( "3 possible \"wrong\" papers each student can receive. 3x3x3x3=81
\n" ); document.write( "81 ways all can receive someone else's paper(?) \n" ); document.write( "

Algebra.Com's Answer #514035 by Fombitz(32388) $\"\"$ $\"About$

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4 items taken 4 at a time gives you 24 possible outcomes
\n" ); document.write( "1 2 3 4
\n" ); document.write( "1 2 4 3
\n" ); document.write( "1 3 2 4
\n" ); document.write( "1 3 4 2
\n" ); document.write( "1 4 2 3
\n" ); document.write( "1 4 3 2
\n" ); document.write( "2 1 3 4
\n" ); document.write( "2 1 4 3
\n" ); document.write( "2 3 1 4
\n" ); document.write( "2 3 4 1
\n" ); document.write( "2 4 1 3
\n" ); document.write( "2 4 3 1
\n" ); document.write( "3 1 2 4
\n" ); document.write( "3 1 4 2
\n" ); document.write( "3 2 1 4
\n" ); document.write( "3 2 4 1
\n" ); document.write( "3 4 1 2
\n" ); document.write( "3 4 2 1
\n" ); document.write( "4 1 2 3
\n" ); document.write( "4 1 3 2
\n" ); document.write( "4 2 1 3
\n" ); document.write( "4 2 3 1
\n" ); document.write( "4 3 1 2
\n" ); document.write( "4 3 2 1
\n" ); document.write( "And only one of these permutations is correct. \n" ); document.write( "

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