document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852328>Question 852328</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in the diagram of parallelogram MATH, angle t is 100 and segment SH bisects angle MHT. What is the measure of angle HSA </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #514014 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=514014\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a parallelogram sum of co-interior angles = 180<BR>\n" );
document.write( "<t+<A = 180<BR>\n" );
document.write( "100+<A = 180<BR>\n" );
document.write( "<A= 80<BR>\n" );
document.write( "opposite angles are equal <BR>\n" );
document.write( "then <H=<A<BR>\n" );
document.write( "<H = 80<BR>\n" );
document.write( "Since S is the bisector of angle MHT, then <BR>\n" );
document.write( "angle HSA = 40 degree </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );