document.write( "Question 853231: A woman has a total of $8,000 to invest. She invests part of the money in an account that pays 5% per year and the rest in an account that pays 9% per year. If the interest earned in the first year is $520, how much did she invest in each account? \n" ); document.write( "
Algebra.Com's Answer #513986 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 5.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 9.00% per annum ------------ Amount invested = y \n" ); document.write( " 8000 \n" ); document.write( "Interest----- 520.00 \n" ); document.write( " \n" ); document.write( "Part I 5.00% per annum ---x \n" ); document.write( "Part II 9.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 8000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "5.00% x + 9.00% y= 520 \n" ); document.write( "Multiply by 100 \n" ); document.write( "5 x + 9 y= 52000.00 --------2 \n" ); document.write( "Multiply (1) by -5 \n" ); document.write( "we get \n" ); document.write( "-5 x -5 y= -40000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 4 y= 12000 \n" ); document.write( "divide by 4 \n" ); document.write( " y = 3000 \n" ); document.write( "Part I 5.00% $ 5000 \n" ); document.write( "Part II 9.00% $ 3000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "5000 --------- 5.00% ------- 250.00 \n" ); document.write( "3000 ------------- 9.00% ------- 270.00 \n" ); document.write( "Total -------------------- 520.00 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |