document.write( "Question 853229: problem: An airplane made a trip of 200 miles against the wind in 1 hour. returning with the wind, the trip took only 50 minutes. Find the speed of the plane in calm air and the speed of the wind\r
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document.write( "For this I'm guessing I have to find two equations that relate speed, time and distance:
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document.write( "I used Y for the speed of the wind and X for the speed of the airplane\r
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document.write( "X-Y = 200m/h\r
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document.write( "X+Y = 200m x 50min \n" );
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Algebra.Com's Answer #513977 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! Let X be the airplane's speed \n" ); document.write( "Let Y be the wind's speed (assuming it is constant) \n" ); document.write( "Here's what we know from the problem: \n" ); document.write( "X - Y = 200 \n" ); document.write( "X + Y = 240 (60min/50 min * 200) \n" ); document.write( "Add together \n" ); document.write( "2X = 440 \n" ); document.write( "X = 220 \n" ); document.write( "If the airplane's speed is 220mph, then the wind is 20mph (Subtract 20 heading into it, add 20 traveling with it). \n" ); document.write( ". \n" ); document.write( "That's exactly what you had, you just needed to go one step further. \n" ); document.write( " |