document.write( "Question 853158: I need help solving this problem. Can you please help me?\r
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document.write( "A survey report states that 70% of adult women visit their doctors for a physical examination at least once in two years. If 20 adult women are randomly selected, find the probability that fewer than 15 of them have had a physical examination in the past two years.\r
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document.write( "Round to three decimal places. \n" );
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Algebra.Com's Answer #513919 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A survey report states that 70% of adult women visit their doctors for a physical examination at least once in two years. If 20 adult women are randomly selected, find the probability that fewer than 15 of them have had a physical examination in the past two years. \n" ); document.write( "------------------------------- \n" ); document.write( "Binomial Problem with n = 20 ; p(visit) = 0.7 ; p(not visit) = 0.3 \n" ); document.write( "----------------------- \n" ); document.write( "P(0<= x <=14) = binomcdf(20,0.7,14) = 0.5836 \n" ); document.write( "=============================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |