document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=853115>Question 853115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which quadratic equation has maximum at (3, 2)?\r<BR>\n" );
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document.write( "Select one:<BR>\n" );
document.write( "a. y = - x2 - 6x - 7<BR>\n" );
document.write( "b. y = -x2 + 6x - 7<BR>\n" );
document.write( "c. y = x2 + 6x - 7<BR>\n" );
document.write( "d.<BR>\n" );
document.write( "y = - x2 - 6x - 7<BR>\n" );
document.write( "y = -x2 + 6x + 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513896 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> completing the Square:<BR>\n" );
document.write( "y = -x2 + 6x - 7 = -(x-3)^2 + 9 - 7<BR>\n" );
document.write( " y = -(x-3)^2 + 2 is a parabola opening downward from V(3,2), it max point<BR>\n" );
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document.write( " </SPAN>\n" );
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