document.write( "Question 853054: \n" );
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Algebra.Com's Answer #513862 by richwmiller(17219) You can put this solution on YOUR website! x/(x-2) for x not = to -3 and x not = to 5 \n" ); document.write( "(x+3)(x-5)=x^2-2x-15 \n" ); document.write( "the denominators cancel each other out.\r \n" ); document.write( "\n" ); document.write( "new numerator \n" ); document.write( "5(x+3)+3*(x-5) \n" ); document.write( "5x+15+3x-15 \n" ); document.write( "8x \n" ); document.write( "new denominator \n" ); document.write( "5*(x-5)+3*(x+3) \n" ); document.write( "5x-25+3x+9 \n" ); document.write( "8x-16 \n" ); document.write( "8*(x-2)\r \n" ); document.write( "\n" ); document.write( "new fraction \n" ); document.write( "8x/8*(x-2) \n" ); document.write( "x/(x-2) \n" ); document.write( " |