document.write( "Question 853046: Hi I am a student studying algebra 2 I do not seem to get how to solve x+y+2z= 11 and x+y+3z=14 and x+2y-z=5 because I am not able to figure out how we get x y and z... \n" ); document.write( "
Algebra.Com's Answer #513853 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "x+y+2z= 11 and
\n" ); document.write( "x+y+3z=14
\n" ); document.write( "x+y+2z= 11 and
\n" ); document.write( "-x-y-3z=-14 |Subtract 2nd from first to eliminate x & y
\n" ); document.write( " -z = -3
\n" ); document.write( " \"+highlight_green%28z+=+3%29\"
\n" ); document.write( "x+y+3z=14 and
\n" ); document.write( "x+2y-z=5
\n" ); document.write( "x+y+9=14 and |Substitute z = 3
\n" ); document.write( "x+2y-3=5
\n" ); document.write( "x+y = 5 and
\n" ); document.write( "x+2y = 8
\n" ); document.write( "x+y = 5 and
\n" ); document.write( "-x-2y = -8 |Subtract 2nd from first to eliminate x
\n" ); document.write( " -y = -3
\n" ); document.write( " \"+highlight_green%28y+=+3%29\" and x+y+2z= 11 ⇒ x + 3 + 6 = 11 \"+highlight_green%28x+=+2%29\"
\n" ); document.write( "(2, 3, 3) the solution for this system \n" ); document.write( "
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