document.write( "Question 853023: I have six answered but not sure if its right. im stuck on number y
\n" ); document.write( "6. Heights of men have a mean of 176 cm and a standard deviation of 7 cm. (based on the data from the National Health Survey). Use the range rule of thumb to estimate the minimum and maximum “usual” heights of men. Charles Darwin had a height of 182 cm. Is Darwin’s height unusual?\r
\n" ); document.write( "\n" ); document.write( "my answer 176-2(7)= 162; 176+2(7)=190, I put that his height is not unusual\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "7. Heights of men have a bell-shaped distribution. Using the Empirical Rule, what is
\n" ); document.write( " the approximate percentage of men between
\n" ); document.write( " a. 155 cm and 197 cm?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " b. 169 cm and 183 cm?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #513848 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "mean of 176 cm and a standard deviation of 7 cm
\n" ); document.write( "182 cm, z = 6/7, < than 1 SD from mean, agree with You.
\n" ); document.write( "between
\n" ); document.write( " a. 155 cm and 197 cm? between 3 SDs from mean ⇒ 99.7%\r
\n" ); document.write( "\n" ); document.write( " b. 169 cm and 183 cm? between 1 SD from mean ⇒ 68% (sometimes 68.3 is used)\r
\n" ); document.write( "\n" ); document.write( "For the normal distribution:
\n" ); document.write( "one standard deviation from the mean accounts for about 68% of the set
\n" ); document.write( "two standard deviations from the mean account for about 95%
\n" ); document.write( "and three standard deviations from the mean account for about 99.7%.
\n" ); document.write( "Important to Understand z -values as they relate to the Standard Normal curve:
\n" ); document.write( "Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.
\n" ); document.write( "Note: z = 0 (x value the mean) 50% of the area under the curve is to the left and %50 to the right
\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "
\n" );