document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=853003>Question 853003</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi. Use the given zero to find the remaining zeros of each function.\r<BR>\n" );
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document.write( "h(x)=x^4-9x^3+21x^2+21x-130            Zero: 3-2i\r<BR>\n" );
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document.write( "So I know that we have 2 zeros now: (x-(3-2i)(x-(3+2i). But how can I proceed? I don't know how to divide the product of those zeros in a synthetic division.\r<BR>\n" );
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document.write( "Many thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513825 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x^2-3x-10)(x^2-6x+13)<BR>\n" );
document.write( "x^2-3x-10= (x+2) (x-5)<BR>\n" );
document.write( "(x+2)(x-5)(x^2-6x+13)<BR>\n" );
document.write( "(x-(3-2i)(x-(3+2i)=(x^2-6x+13)<BR>\n" );
document.write( "the zeros must be factors of -130<BR>\n" );
document.write( "the prime factors are -2󬊁3<BR>\n" );
document.write( "There are only a few to test<BR>\n" );
document.write( "-2, 2, -5 and 5 , -13 and 13\r<BR>\n" );
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document.write( " </SPAN>\n" );
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