document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852880>Question 852880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of the six trigonometric functions for an angle 0 in standard position if point P(-5,5sqrt(3))is on its terminal side.\r<BR>\n" );
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document.write( "I need help with this please! Thanks!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513817 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of the six trigonometric functions for an angle 0 in standard position if point P(-5,5sqrt(3))is on its terminal side. <BR>\n" );
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document.write( "Plot the point.<BR>\n" );
document.write( "Notice it in QII.<BR>\n" );
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document.write( "You have x = -5 and y = 5sqrt(3)<BR>\n" );
document.write( "So, r = sqrt[5^2 + (5sqrt(3))^2]<BR>\n" );
document.write( "r = sqrt[25 + 75] = 10<BR>\n" );
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document.write( "sin = y/r = 5sqrt(3)/10 = (1/2)sqrt(3)<BR>\n" );
document.write( "cos = x/r = -5/10 = -1/2<BR>\n" );
document.write( "tan = y/x = 5sqrt(3)/-5 = -sqrt(3)<BR>\n" );
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document.write( "csc = r/y = 2/sqrt(3)<BR>\n" );
document.write( "sec = r/x = -2<BR>\n" );
document.write( "cot = x/y = -1/sqrt(3)<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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