Algebra.Com's Answer #51381 by Earlsdon(6294)![\"\"](\"/images/stars/stars-13.gif\")  
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Factor:
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document.write( "(a)  Notice that the first and last terms are perfect squares. This suggests the possibility that the expression itself may be a perfect square. Since  , you can try:
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document.write( "Check using FOIL:
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document.write( " = 
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document.write( "The factors are:  and
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document.write( "(b)  Here, you use use \"factor by grouping\". Group the terms as folows:
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document.write( " Notice the change of sign on the last term when the parentheses were added. Now, from each group, factor the common factors.
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document.write( " Now you can factor the common factor of (y+7)
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document.write( " These are the factors.
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document.write( "Solve:
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document.write( "(c)  This will factor. Notice that the last term has factors of 4 and 5. Also notice that 4-5 = -1 and this is the coefficient of the middle term. So we try:
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document.write( " Apply the zero product principle:
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document.write( " and/or 
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document.write( "If then 
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document.write( "If then 
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document.write( "The roots are:
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document.write( "(d)
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document.write( " Notice that both sides are perfect squares.
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document.write( " Take the square root of both sides.
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document.write( " or  Divide both sides by 3.
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document.write( " or  \n" );
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