document.write( "Question 852943:
\n" ); document.write( "Janine invested one part of her $20,000 savings at 8% per year and the other part at 9% per year. Her income from the two investments was $1,650 after one year. How much did she invest at each rate?
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Algebra.Com's Answer #513772 by checkley79(3341)\"\" \"About 
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.08X+.09(20,000-X)=1,650
\n" ); document.write( ".08X+1,800-.09X=1,650
\n" ); document.write( "-.01X=1,650-1,800
\n" ); document.write( "-.01X=-150
\n" ); document.write( "X=-150/.01=15,000 INVESTED @8%.
\n" ); document.write( "20,000-15,000=5,00 INVESTED @9%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".08*15,000+.09*5,000=1,650
\n" ); document.write( "1,200+450=1,650
\n" ); document.write( "1,650=1,650\r
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