document.write( "Question 852943:
\n" ); document.write( "Janine invested one part of her $20,000 savings at 8% per year and the other part at 9% per year. Her income from the two investments was $1,650 after one year. How much did she invest at each rate? \n" ); document.write( "

Algebra.Com's Answer #513771 by ramkikk66(644) $\"\"$ $\"About$

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document.write( "Janine invested one part of her $20,000 savings at 8% per year and the other part at 9% per year. Her income from the two investments was $1,650 after one year. How much did she invest at each rate?\r\n" );
document.write( "Ans:\r\n" );
document.write( "Let her invest x at the rate of 8%\r\n" );
document.write( "So amount invested at 9% is 20000 - x\r\n" );
document.write( "Interest at 8% = 0.08*x\r\n" );
document.write( "Interest at 9% = 0.09*(20000 - x)\r\n" );
document.write( "Total interest = \r\n" );
document.write( "Simplifying\r\n" );
document.write( " or \r\n" );
document.write( "So she invests $15000 at 8%, and $5000 at 9%.\r\n" );
document.write( "Check: Interest = 15000*0.08 + 5000 * 0.09 = 1200 + 450 = 1650. Correct!\r\n" );
document.write( "Hope this helps.\r\n" );
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