document.write( "Question 852935: The age of employees (in years) in a particular industry has a normal distribution with mean of 38 and standard deviation of 5.9. Only 2% of employees are younger than what age?
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Algebra.Com's Answer #513770 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "2% ⇒ z = NORMSINV(.02) = Z = -2.0538
\n" ); document.write( "mean of 38 and standard deviation of 5.9.
\n" ); document.write( " -2.0538 = (X-38)/5.9
\n" ); document.write( "\"5.9%28-2.0538%29+%2B+38+\"= 25.88 0r 26 rounded Up
\n" ); document.write( "2% of employees are younger than 26
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