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document.write( "Find 3 consecutive integers in which the sum of 1st and 3rd is 84 more than one half of the 2nd
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Algebra.Com's Answer #513763 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! YOU HAVE: \n" ); document.write( "X the first integer \n" ); document.write( "X+1 the second integer \n" ); document.write( "x+2 the third integer \n" ); document.write( "x+(x+2)=84+(x+1)/2 \n" ); document.write( "2x+2=84+(x+1)/2 \n" ); document.write( "2x-(x+1)/2=84-2 combine the 2 x terms. \n" ); document.write( "(4x-x-1)/2=82 \n" ); document.write( "(3x-1)/2=82 cross multiply \n" ); document.write( "3x-1=2*82 \n" ); document.write( "3x-1=164 \n" ); document.write( "3x=164+1 \n" ); document.write( "3x=165 \n" ); document.write( "x=165/3 \n" ); document.write( "x=55 the first integer. \n" ); document.write( "55+1=56 the second integer. \n" ); document.write( "55+2=57 the third integer. \n" ); document.write( "Proof: \n" ); document.write( "55+57=84+56/2 \n" ); document.write( "112=84+28 \n" ); document.write( "112=112 \n" ); document.write( " |