document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852862>Question 852862</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An operation has a 15 percent scrap rate. As a result, 64 pieces per hour are produced. What is the potential increase in labor productivity that could be achieved by eliminating the scrap? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513739 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39627)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This operation which produced the  64 pieces also produced 15% scrap.  100-15=85, so the 64 pieces produced is 85% of {good pieces + scrap}.  Call that brace-enclosed quantity, T.  0.85T=64 pieces, so T=75.294, approximately to five figures.  The scrap produced for this 64 good pieces was 0.15(75.294)=11.294 scrap pieces.\r<BR>\n" );
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document.write( "The increase in productivity if that 11.294 amount scrap were good instead of scrap would be ...  think about it ....   <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2885%2B15%29%2F85=1.17647 ALIGN=MIDDLE  ALT=\"%2885%2B15%29%2F85=1.17647\"   DISABLED_style= \"max-width:90%; height:auto;\" >... approximately, close enough to 17.6% increase in productivity. </SPAN>\n" );
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