document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71899>Question 71899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 12 more than another.  The sum of the smaller number and twice the larger number is 39.  Find the larger number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51371 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first number = x.<BR>\n" );
document.write( "Then the other number = 12 more than 'x' = (x+12).\r<BR>\n" );
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document.write( "Clearly, 'x' is the smaller number and (x+12) is the larger.<BR>\n" );
document.write( "So the sum of the smaller number and twice the larger number = x + 2(x + 12) = 39<BR>\n" );
document.write( "i.e. x + 2(x + 12) = 39<BR>\n" );
document.write( "x + 2x + 2*12 = 39<BR>\n" );
document.write( "3x + 24 = 39<BR>\n" );
document.write( "3x = 39 - 24 <BR>\n" );
document.write( "3x = 15<BR>\n" );
document.write( "x = 15/3<BR>\n" );
document.write( "x = 5\r<BR>\n" );
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document.write( "So the smaller number = x = 5 and the larger number = (x + 12) = 5 + 12 = 17\r<BR>\n" );
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document.write( "Answer: 17 </SPAN>\n" );
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