document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852841>Question 852841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of Jessie and Maryann’s ages is 42 years. In 12 years, Maryann’s age will be double Jessie’s current age. What is Maryann’s present age, in years? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513705 by </B><A HREF=/tutors/aboutme.mpl?userid=Seutip><B>Seutip(231)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Seutip><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Seutip><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513705\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In 12 years:\r<BR>\n" );
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document.write( "Jessie - x<BR>\n" );
document.write( "Maryann - 2x\r<BR>\n" );
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document.write( "Present:\r<BR>\n" );
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document.write( "Jessie - x-12<BR>\n" );
document.write( "Maryann - 2x-12\r<BR>\n" );
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document.write( "x-12+2x-12=42<BR>\n" );
document.write( "3x-24=42<BR>\n" );
document.write( "3x=18<BR>\n" );
document.write( "x=6\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "Jessie is 6 while Maryann is 12. :)\r<BR>\n" );
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document.write( "Hope that helps!\r<BR>\n" );
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