document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71843>Question 71843</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a fenced yard with a lenght of 110 feet and  width of 65 feet.<BR>\n" );
document.write( "   Thanks  Tutor. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51367 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Are you asking for the perimeter or the area?<BR>\n" );
document.write( "Area = (Length)(Width)<BR>\n" );
document.write( "A=(110)(65)=7510 sq. feet<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Perimeter=2(Length + width)<BR>\n" );
document.write( "P=2(110+65)<BR>\n" );
document.write( "P=2(175)<BR>\n" );
document.write( "P=350 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );