document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852584>Question 852584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 52 feet. the length is 2 feet shorter than three times the width. find the area of the rectangle in square feet. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513523 by </B><A HREF=/tutors/aboutme.mpl?userid=Seutip><B>Seutip(231)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Seutip><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Seutip><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513523\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x   -be the width<BR>\n" );
document.write( "   3x-2 -be the length\r<BR>\n" );
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document.write( "P=2w+2x<BR>\n" );
document.write( "52=2x+2(3x-2)<BR>\n" );
document.write( "52=2x+6x-4<BR>\n" );
document.write( "52=8x-4<BR>\n" );
document.write( "48=8x<BR>\n" );
document.write( "x=6\r<BR>\n" );
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document.write( "Width =6 ft<BR>\n" );
document.write( "Length =16\r<BR>\n" );
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document.write( "A=lw<BR>\n" );
document.write( "A=(6ft)(16ft)<BR>\n" );
document.write( "A=96 sqft.\r<BR>\n" );
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document.write( "Hopethat helps!\r<BR>\n" );
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