document.write( "Question 852430: log2(x)+log2(x+1)=log2(6) \n" ); document.write( "
Algebra.Com's Answer #513500 by LinnW(1048)\"\" \"About 
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log2(x)+log2(x+1)=log2(6)
\n" ); document.write( "log2(x)+log2(x+1) = log2(6)
\n" ); document.write( "log2(x*(x+1))) = log2(6)
\n" ); document.write( "log2(x*(x+1))) = log2(6)
\n" ); document.write( "log2(x^2 + x) = log2(6)
\n" ); document.write( "x^2 + x = 6
\n" ); document.write( "add -6 to each side
\n" ); document.write( "x^2 + x -6 = 0
\n" ); document.write( "(x + 3)(x - 2) = 0
\n" ); document.write( "x = -3 or x = 2
\n" ); document.write( "-3 does not work with the original equation, so x = 2
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