document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852499>Question 852499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three numbers are in the ratio 2:5:8 . If 10 is added to the middle number, the number form a G P. Find the numbers?  Plz help me solve this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513415 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513415\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> three numbers in ratio 2:5:8<BR>\n" );
document.write( "let these numbers are  2x:5x:8x<BR>\n" );
document.write( "as per given conditions if 10 is added to middle number<BR>\n" );
document.write( "number forms GP(if a,b,c are GP than b^2=ac)<BR>\n" );
document.write( "2x,5x+10,8x<BR>\n" );
document.write( "(5x+10)^2=2x multiplied by 8x<BR>\n" );
document.write( "25x^2+100x+100=16x^2<BR>\n" );
document.write( "9x^2+100x+100=0<BR>\n" );
document.write( "9x^2+90x+10x+100=0<BR>\n" );
document.write( "9x(x+10)+10(x+10)=0<BR>\n" );
document.write( "(x+10)(9x+10)=0<BR>\n" );
document.write( "x=-10 or x=-10/9<BR>\n" );
document.write( "neglecting n second value as it can not be fractional  we consider x=-10<BR>\n" );
document.write( "numbers are 2x:5x:8x<BR>\n" );
document.write( "          =-20:-50:-80<BR>\n" );
document.write( "verification<BR>\n" );
document.write( "(-50+10)^2= -20 multiplied by -80<BR>\n" );
document.write( "1600=1600<BR>\n" );
document.write( "verified  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );